rdzeń śruby:

R_w = R₀ − R₁s

$$\sigma_{c} = \frac{4Q}{\pi{d_{r}}^{2}}$$

$$\sigma_{c} = \frac{R_{w}}{x_{w}}$$

$$\frac{4Q}{\pi{d_{r}}^{2}} \leq \frac{R_{0} - R_{1}s}{x_{w}}$$

$$s = \frac{4l_{w}}{d_{r}}$$

l_w = 2(H + 100)

$$\frac{4Q}{\pi{d_{r}}^{2}} \leq \frac{R_{0} - R_{1}\frac{4l_{w}}{d_{r}}}{x_{w}}$$

$$R_{0}{d_{r}}^{2} - 4R_{1}l_{w}d_{r} - \frac{4Qx_{w}}{\pi} = 0$$

$$= {( - 4R_{1}l_{w})}^{2} - 4R_{0}( - \frac{4Qx_{w}}{\pi})$$

warunek nieprzekraczania dopuszczalnych nacisków spoczynkowych

p_rzeczspocz ≤ p_dopspocz

$$p_{\text{rzeczspocz}} = \frac{Q}{\begin{matrix} \frac{\pi}{4}\left( {d_{\text{zn}}}^{2} - {d_{\text{otw}}}^{2} \right) \\ \\ \end{matrix}}$$

$$p_{\text{rzeczspocz}} \times \frac{\pi}{4}\left( {d_{\text{zn}}}^{2} - {d_{\text{otw}}}^{2} \right) = Q$$

średnica zewnętrzna nakrętki

$$d_{\text{zn}} = \sqrt{\frac{Q}{p_{\text{rzeczspocz}} \times \frac{\pi}{4}} + {d_{\text{otw}}}^{2}}$$

$$p_{\text{rzeczruch}} = \frac{Q}{\frac{\pi}{4}({d_{r}}^{2} - {D_{\text{otwnakr}}}^{2})n}$$

$$n = \frac{4Q}{\pi p_{\text{rzeczruch}}({d_{r}}^{2} - {D_{\text{otwnakr}}}^{2})}$$

wysokość nakrętki

H_n = (n+1,5)p

wyjściowa średnica do toczenia śruby

d_t = 1, 5d

d_cz = 1, 5d − 10

$$p_{\text{rzeczywiste}} = \frac{Q}{\frac{\pi}{4}\left( {d_{\text{cz}}}^{2} - {d_{0}}^{2} \right)}$$

momenty sił

M_t = 0, 5 × Q × d_m × μ

$$d_{m} = \frac{d_{\text{cz}} + d_{0}}{2}$$

M_s = 0, 5 × Q × d_sr × tg(γ + ρ′)

$$tg\gamma = \frac{p}{\pi \times d_{sr}}$$

$$tg\rho' = \frac{\mu}{\cos\frac{\alpha}{2}}$$

$$\sigma_{c} = \frac{4Q}{\pi{d_{\min}}^{2}}$$

$$\tau_{\text{Ms}} = \frac{M_{s}}{W_{0}}$$

$$\sigma_{\text{zast}} = \sqrt{{\sigma_{c}}^{2} + 3{\tau_{\text{Ms}}}^{2}}$$

korpus

$$p = \frac{4Q}{\pi({D_{p}}^{2} - {d_{w}}^{2})}$$

$$D_{p} = \sqrt{\frac{4Q}{\text{pπ}} + {d_{w}}^{2}}$$

$$\sigma_{g} = \frac{M_{g}}{W_{x}}$$

M_g = Qa

a=D_p − d

d = d_rury + 10

$$W_{x} = \frac{\text{Qa}}{\sigma_{g}}$$

$$W_{x} = \frac{bh^{2}}{6}$$

$$h = \sqrt{\frac{6W_{x}}{b}}$$

śruba zabezpieczająca

$$k_{r} = \frac{R_{0}}{x_{sr}}$$

$$wk_{r} \geq \frac{0,5Q}{\frac{\pi}{4}{d_{1}}^{2}} = \sigma_{\text{rzecz}}$$

$$d_{1} = \sqrt{\frac{0,5Q}{wk_{r}\frac{\pi}{4}}}$$

długość drąga

M_c = M_t + M_s = R × F_r

$$R = \frac{M_{t} + M_{s}}{F_{r}}$$