6

15

16

15

60°

6°

6°

4,29

P

S

6

5

3

2

4

A

c

B

D

M

T
2

V

54

V

45

P

T

45

P

T

54

V

34

V

43

P

T

43

=P

T

32

P

T

34

=P

T

23

1

P

T

12

P

T

21

P

(T)
56

P

T

16B

P

s

P

T

16A

P

T

54

P

T

34

P

T

14

P

T

54

=9.64 kN

P

T

34

=10.98 kN

P

T

14

=2.49 kN

1

P

T

16A

=1.67kN

P

(T)
56

=9.64kN

P

T

16B

=2.42kN

P

T

12

=-P

T

32

∑M

2

=P

T

32

*h

T

32

-P

T

12

*h-M

T

2

=0

M

T

2

=

P

T

32

*h

T

32

-P

T

12

*h

P

T

32

=10.98kN

P

T

12

=10.98kN

h

T

32=0.0429m

h=0.008m

M

T

2

=0.383

kN

m

Bartłomiej Morawa 165361 wtorek 11.15

zad.159 siły z tarciem