15
6°
Ps
6
P T16A
P T16B
6
P(T)56
16
PS
P T =1.67kN
16A
5 V45 V54
P(T)=9.64kN
56
P T
P T
45
54
P T =2.42kN
D
16B
4,29
P T =P T
34
23
3
B
P T =P T
60° 43 32
P T
2 MT2
V34
12
V
P T54
A
43
P T21
4
P T14
1
P T
15
34
∑M
T
P T =9.64 kN
2=P T
32*h T
32-P T
12*h-MT2=0
PT32=10.98kN
h
54
32=0.0429m P T =10.98 kN
34
T
PT12=10.98kN
h=0.008m P T =2.49 kN
M
14
2=PT32*hT32-PT12*h P T12=-P T32
T
kN
c
M2=0.383m 1
Bartłomiej Morawa 165361 wtorek 11.15