Obieg Rankina
1 B • Qw • ηk + Diwz = Di0
2 $\text{Di}_{1} = \frac{\text{Nel}}{\eta_{m} \bullet \eta_{g}} + D_{ik'}$
3 $\text{Di}_{k'} + D_{\text{wchI}} \bullet i_{\text{wchI}} = \text{Di}_{k"} \bullet D_{\text{wchII}} \bullet i_{\text{wchII}}$
$$\eta_{\text{el}} = \frac{\text{Nel}}{B \bullet Qw}$$
$$\eta_{\text{ob}} = \frac{i_{1} - i_{k'}}{i_{0} - i_{\text{wz}}}$$
$${n'}_{C} = \frac{C\%}{100 \bullet 12}$$
$${n'}_{H2} = \frac{H\%}{100 \bullet 2 \bullet 1}$$
$${n'}_{O2} = \frac{O\%}{100 \bullet 2 \bullet 16}$$
$${n'}_{N2} = \frac{N\%}{100 \bullet 2 \bullet 14}$$
$${n'}_{S} = \frac{S\%}{100 \bullet 32}$$
$${n'}_{W} = \frac{W\%}{100 \bullet (2 \bullet 1 + 16)}$$
$$n_{O_{2\ \text{teor}.}} = {n'}_{C} + {n'}_{S} + \frac{1}{2}{n'}_{H2} - {n'}_{O2}$$
VO2t = 22, 42 • nO2 t.
$$V_{\text{powt}} = \frac{V_{O2t}}{0,21}$$
Vpowrz = Vpowt • λ
$$V_{\text{pow}}^{w} = V_{\text{powrz}} \bullet B \bullet \frac{273,15 + t_{\text{pow}}}{273,15}$$
$${n"}_{\text{sw}} = {n"}_{\text{ss}} + {n"}_{w}$$
$${n"}_{\text{ss}} = {n"}_{\text{CO}2} + {n"}_{\text{CO}} + {n"}_{\text{SO}2} + {n"}_{N2} + {n"}_{O2}$$
$${n"}_{\text{ss}} = \frac{{n'}_{C} - {n"}_{C}}{{\lbrack\text{CO}\rbrack}_{\%} + {{\lbrack\text{CO}}_{2}\rbrack}_{\%}}$$
$${n'}_{C} = {n"}_{\text{CO}2} + {n"}_{\text{CO}} + {n"}_{C}$$
$${n"}_{\text{SO}2} = {n'}_{S}$$
$${n"}_{N2} = {n'}_{N2} + 0,79\frac{n_{O2}t \bullet \lambda}{0,21}$$
$${n"}_{O2} = \left( \lambda - 1 \right) \bullet n_{O2t} + \frac{1}{2}{n"}_{\text{CO}} + {n"}_{C}$$
$${n"}_{W} = {n'}_{H2} + {n'}_{H2O}$$
$$V_{\text{sp}} = 22,42 \bullet {n"}_{\text{sw}}$$
$$V_{\text{sp}}^{w} = V_{\text{sp}} \bullet B \bullet \frac{273,15 + t_{\text{sp}}}{273,15}$$
$$\left\lbrack \text{CO} \right\rbrack_{\%} = \frac{{n"}_{\text{CO}}}{{n"}_{\text{SS}}} \bullet 100\%$$
$$\ {(\text{CO})}_{\%} = \frac{{n"}_{\text{CO}}}{{n"}_{\text{SW}}} \bullet 100\%$$
Ciepło właściwe
$$\text{Qw} = 33,9 \bullet C\% + 121\left( H\% - \frac{O\%}{8} \right)$$
+10, 4 • S%−2, 5 • W%
Met. Bezpośrednia
$$\eta_{k\%} = \frac{D\left( i_{0} - i_{\text{wz}} \right)}{B \bullet Qw} \bullet 100\%$$
Met. pośrednia
ηk% = 100 − (Sg%+Sn%+Sw%+Spr%+Sz%)
$$S_{g\%} = \frac{12628 \bullet {n"}_{\text{CO}} \bullet 22,42}{\text{Qw}} \bullet 100\%$$
$S_{n\%} = \frac{33900 \bullet {n"}_{C} \bullet 12}{\text{Qw}} \bullet 100$%