29.
(a) P
avg
= (15
× 10
9
W
·y)/(200, 000 y) = 7.5 × 10
4
W = 75 kW.
(b) Using the result of Eq. 44-6, we obtain
M
=
m
U
E
total
Q
=
(235 u)(1.66
× 10
−27
kg/u)(15
× 10
9
W
·y)(3.15 × 10
7
s/y)
(200 MeV)(1.6
× 10
−13
J/MeV)
=
5.8
× 10
3
kg .
29.
(a) P
avg
= (15
× 10
9
W
·y)/(200, 000 y) = 7.5 × 10
4
W = 75 kW.
(b) Using the result of Eq. 44-6, we obtain
M
=
m
U
E
total
Q
=
(235 u)(1.66
× 10
−27
kg/u)(15
× 10
9
W
·y)(3.15 × 10
7
s/y)
(200 MeV)(1.6
× 10
−13
J/MeV)
=
5.8
× 10
3
kg .