36.
(a) For the minimum (43 cm) case, 9 cubit converts as follows:
(9 cubit)
0.43 m
1 cubit
= 3.9 m .
Andfor the maximum (43 cm) case we obtain
(9 cubit)
0.53 m
1 cubit
= 4.8 m .
(b) Similarly, with 0.43 m
→ 430 mm and0.53 m → 530 mm, we find3.9×10
3
mm and4.8
×10
3
mm,
respectively.
(c) We can convert length anddiameter first andthen compute the volume, or first compute the volume
andthen convert. We proceedusing the latter approach (where d is diameter and is length).
V
cylinder, min
=
π
4
d
2
= 28 cubit
3
=
28 cubit
3
0.43 m
1 cubit
3
=
2.2 m
3
.
Similarly, with 0.43 m replacedby 0.53 m, we obtain V
cylinder, max
= 4.2 m
3
.